php
/
xinnongbaohe


			
				
					
						
						
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							<!DOCTYPE html>
<html>

	<head>
		<meta charset="utf-8">
		<meta name="viewport" content="width=device-width,initial-scale=1,minimum-scale=1,maximum-scale=1,user-scalable=no" />
		<title></title>
		<link href="css/mui.min.css" rel="stylesheet" />
		<link href="css/main.css" rel="stylesheet" />
	</head>

	<body>
		<header class="mui-bar mui-bar-nav">
			<a class="mui-action-back mui-icon mui-icon-left-nav mui-pull-left"></a>
			<h1 class="mui-title" id="title">消息通知</h1>
		</header>

		<div class="mui-content">
			<div class="mui-control-content mui-active">
			<iframe id="message" src="" style="width:100%;overflow: hidden;border:0px;"></iframe>
			</div>

		</div>

		<script src="js/mui.min.js"></script>
		<script src="js/main.js"></script>
		<script type="text/javascript" charset="utf-8">
			(function($, self) {
				$.init();
				$.plusReady(function() {
					plus.webview.currentWebview().setStyle({scrollIndicator:'none'});

					var page = document.getElementById("message");
					//alert(winSize().height);
					page.setAttribute('height', winSize().height);
					//alert(page.getAttribute('height'));
					page.setAttribute('src', config.host + 'message?header=false&');
					
					window.addEventListener('resize', function() {
						oauthArea.style.display = document.body.clientHeight > 400 ? 'block' : 'none';
					}, false);
					/*
					//处理逻辑：1秒内，连续两次按返回键，则退出应用；
				    var first = null;
				    plus.key.addEventListener('backbutton', function(){
				        //首次按键，提示‘再按一次退出应用’
				        if(!first){
				            first = new Date().getTime();
				            mui.toast('再按一次退出应用');
				            setTimeout(function(){
				                first = null;
				            },1000);
				        }else{
				            if(new Date().getTime()-first<1000){
				                plus.runtime.quit();
				            }
				        }
				    }, false);
				    */
				});
			}(mui, document));
		</script>
	</body>

</html>